7^2x+1=1/7

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Solution for 7^2x+1=1/7 equation: 



7^2x+1=1/7

We move all terms to the left:

7^2x+1-(1/7)=0

We add all the numbers together, and all the variables

7^2x+1-(+1/7)=0

We get rid of parentheses

7^2x+1-1/7=0

We multiply all the terms by the denominator


7^2x*7-1+1*7=0

We add all the numbers together, and all the variables

7^2x*7+6=0

Wy multiply elements

49x^2+6=0

a = 49; b = 0; c = +6;
Δ = b2-4ac
Δ = 02-4·49·6
Δ = -1176
Delta is less than zero, so there is no solution for the equation

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